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Lesson 39

Modeling with Exponential and Logarithmic Functions

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Hello! Welcome to the final lesson in our module on Exponential and Logarithmic Functions.

In our last session, we focused on solving logarithmic equations. The key skills you mastered were condensing logarithmic expressions and then converting them into exponential form to find the variable. A crucial part of that process was the need to check for extraneous roots, ensuring the arguments of the logarithms remained positive. That skill of using logarithms to "undo" exponentials will be absolutely central to what we do today.

This lesson's learning outcome is to model real-world situations, such as compound interest and population growth, using exponential and logarithmic functions. We will see how the abstract functions we've been studying are powerful tools for describing and predicting phenomena in finance, science, and technology. This session will bring together everything you've learned about indices (exponents), e, and logarithms into practical application.

1. The Power of Compounding: Exponential Growth

Many processes in the real world, from financial investments to population sizes, don't grow by a fixed amount each year. Instead, they grow by a certain percentage of their current value. This leads to exponential growth. The most common example is compound interest.

Let's start by clarifying the difference between simple and compound interest.

  • Simple Interest: Interest is calculated only on the original amount (the principal). This results in linear growth.
  • Compound Interest: Interest is calculated on the principal plus any accumulated interest. The interest earns interest, leading to exponential growth.
Comparison of Compound and Simple Interest Growth
This graph visually compares the linear growth of simple interest (blue line) with the accelerating, exponential growth of compound interest (red curve). The difference becomes more dramatic over time.

Compound Interest - GCSE Maths

The following video from the British channel 1st Class Maths provides a clear introduction to these concepts. It walks through how to calculate both simple and compound interest and establishes the core idea of a repeated percentage change.

Please watch the video from the beginning until 08:12. Pay attention to: The difference in the calculation method between simple and compound interest. How a percentage increase is represented by a 'multiplier' (e.g., a 5% increase is a multiplier of 1.05). How this leads to the compound interest formula involving an index (exponent).

As the video demonstrates, for interest compounded annually, the formula is:

Where:

  • is the final amount.
  • is the principal (the initial amount).
  • is the annual interest rate as a decimal (e.g., 5% = 0.05).
  • is the number of years.

This same model applies to any situation involving a repeated percentage change over discrete time periods. For example, exponential decay, such as a car's value depreciating by 15% per year, would use a similar formula:

Here, the multiplier is less than 1, causing the value to decrease over time. The video you'll see later (LINK from 21:14 onwards) also gives an example of this with car depreciation.


2. The Continuous Model: Where e Shines

While some things are measured in discrete steps (like annual interest), many natural processes—like population growth, radioactive decay, or heat dissipation—happen continuously. In these cases, the number provides the most natural base for our model.

The standard form for continuous growth or decay is:

Where:

  • is the amount at time .
  • is the initial amount at .
  • is the continuous growth or decay rate.
    • If , it represents exponential growth.
    • If , it represents exponential decay.
  • is time.

Let's look at how this is applied.

Modelling Exponential Growth and Decay | Revision

The webpage 'Modelling Exponential Growth and Decay' from MME Revise provides some excellent, straightforward examples of setting up and using this model.

Please read the first two worked examples on the page: The first example on radioactive decay, starting with R = Ae^(-0.05t). The example labeled 'Question 3' about city population growth, starting with P = 10000e^(0.1(t-2008)). Focus on how the initial conditions are used to find the value of the constants.

In finance, you might also see the term continuously compounded interest. This is the theoretical limit as the compounding periods (like monthly, daily, hourly) become infinitely small. The formula for this is a direct application of our continuous model:

Here, is the principal, is the annual interest rate, and is the time in years.

Compound Interest & Population Growth Word Problems - Logarithms

The following video from The Organic Chemistry Tutor introduces a more general formula for interest compounded n times per year, and then shows how it simplifies to the Pe^(rt) formula for the continuous case.

Watch the segment from the beginning until 02:55. Notice the introduction of the variable n for the number of compounding periods per year and the separate, simpler formula used for continuous compounding.


3. Finding Time: Putting Your Logarithm Skills to Work

A very common and important task is to determine how long it will take for a quantity to reach a certain value. How long will it take for an investment to double? What is the half-life of a radioactive substance?

To answer these questions, we need to solve for in our exponential model. This is where your skills from the previous lesson become essential.

Example: Doubling Time

An initial population of 200 dogs on an island grows continuously at a rate of 6% per year. The model is . How long will it take for the population to double to 400 dogs?

  1. Set up the equation: We want to find when .

  2. Isolate the exponential term: Divide both sides by the initial amount, 200.

    (Notice that for any doubling-time problem, the equation always simplifies to this form!)

  3. Take the natural logarithm of both sides: This is the key step to bring the exponent down.

  4. Use the logarithm property :

  5. Solve for :

This exact process is used for finding half-life (where the ratio is 0.5 instead of 2) or any other target value.

Compound Interest & Population Growth Word Problems - Logarithms

The Organic Chemistry Tutor video demonstrates this process perfectly. Watch how logarithms are used to solve for time t in both a financial and a population context.

Please watch these two segments: Finding Doubling Time (02:55 - 05:38): This works through a compound interest problem, solving for t when the account doubles. Finding Population Time (07:37 - 09:40): This finds the year a population will reach a specific target number.

Test your understanding!

The radioactive substance Carbon-14 decays continuously with a decay rate of about . Its decay is modelled by . Calculate the half-life of Carbon-14. (This is the time it takes for half of the substance to decay).

Show answer
  1. Set up the equation: For half-life, the final amount is half the initial amount . So, .

  2. Isolate the exponential: Divide by .

  3. Take the natural log:

  4. Simplify:

  5. Solve for :

    So, the half-life of Carbon-14 is approximately 5,776 years.


4. A Note on Model Limitations: Growth Isn't Forever

The exponential growth model predicts that a quantity will increase without any bound, getting faster and faster forever. While this is a good model for the early stages of growth, in the real world, there are almost always limiting factors. A bacterial colony will run out of food and space; a predator population is limited by the availability of prey.

A more refined model that accounts for this is logistic growth, where the growth rate slows down as the population approaches an environmental "carrying capacity".

Exponential versus Logistic Population Growth
This image shows the difference between the unlimited exponential model (left) and the more realistic logistic model (right), which levels off at a carrying capacity (K).

The logistic model has a more complex equation, but it's a great example of how mathematicians and scientists refine models to better fit reality. For our purposes, the key is to recognise that the exponential model is a powerful but sometimes simplified representation of the world.


Conclusion

This lesson marks the culmination of our work with exponential and logarithmic functions. We've seen how these are not just abstract mathematical objects, but essential tools for modelling the world around us.

Key Takeaways:

  • Phenomena involving a repeated percentage change can be modelled with exponential functions.
  • Discrete change (e.g., annual interest) is often modelled by .
  • Continuous change (e.g., population growth, radioactive decay) is best modelled by .
  • Logarithms are the essential tool we use to solve for time (t) in these models, particularly for finding doubling times or half-lives.
  • All models are simplifications, and it's important to consider their limitations, such as the unchecked growth predicted by the basic exponential model.

Preview of the Next Lesson:

We have now completed the "Exponential and Logarithmic Functions" module. You've built a strong foundation, from the basic rules of indices all the way to applying these functions in sophisticated ways.

In our next lesson, we will pivot to an entirely new and fascinating branch of mathematics: Trigonometry. We'll start from the very beginning, exploring the relationships between the angles and side lengths in right-angled triangles.