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Lesson 30

Prisms and Dispersion: NEET Problem Solving

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Hello! Welcome to our final lesson on prisms.

In the last few lessons, we've built a complete toolkit for analyzing light passing through a prism. We derived the main prism formula, explored the special case of minimum deviation, understood dispersion qualitatively, and then quantified it with the formulas for angular dispersion and dispersive power.

Today, we put it all together. As you requested, this session is designed as a vigorous workout to sharpen your problem-solving skills for the NEET exam. Our goal is to solve a variety of NEET-style problems involving prisms and dispersion. We will tackle different scenarios, from minimum deviation to combinations of prisms, applying the formulas we've learned.

Let's briefly recap our key formulas:

  1. Prism Formula (at minimum deviation, ):
  2. Thin Prism Deviation:
  3. Angular Dispersion (for thin prisms):
  4. Dispersive Power:

Let's dive into applying these in a problem-solving context.

1. Problems on Minimum Deviation

The condition of minimum deviation is a favorite for examiners because of its unique properties: the angle of incidence equals the angle of emergence (), the internal refracted ray is parallel to the prism's base, and the two internal angles are equal ().

Experiment on Refraction Through a Glass Prism
This diagram shows both the path of light through a prism and the characteristic graph of deviation vs. incidence angle. The lowest point on the curve represents the angle of minimum deviation, \(\delta_m\), which occurs at a specific angle of incidence.

Let's watch a segment where these concepts are used to solve a few typical exam questions.

Ray optics L5 🔍 Prism, dispersion & combination |One Shot Marathon | Class 12 JEE 2022 | Shreyas sir

The following video from Vedantu JEE English demonstrates how to approach problems involving the condition of minimum deviation. Pay attention to how the properties of minimum deviation (i=e, r_1=r_2) simplify the problem.

Watch the segment from 00:39:00 to 00:46:58. The instructor solves three problems: one using the symmetry condition, one using the deviation formula \delta = i_1+i_2-A, and one using Snell's law.

The key strategies you saw were:

  • For minimum deviation, you can immediately set and .
  • The general deviation formula simplifies to , which is often a faster way to find or than using the full prism formula.
  • You can always fall back on applying Snell's Law at the first surface: .
Test your understanding!

A prism has a refracting angle of 60°. When placed in the position of minimum deviation, it produces a deviation of 30°. What is the angle of incidence?

(This is question 139 from the practice PDF LINK)

Show answer

We can use the simplified formula for minimum deviation: .
Given:

Rearranging for the angle of incidence :

The angle of incidence is 45°.


2. Problems on Thin Prisms and Dispersion

For thin prisms (), the small angle approximation simplifies our calculations significantly. The formula is the starting point for all problems in this category.

Let's watch two worked examples, one of which involves a common variation: placing a mirror after the prism.

Ray optics L5 🔍 Prism, dispersion & combination |One Shot Marathon | Class 12 JEE 2022 | Shreyas sir

This next clip, also from Vedantu, solves problems using the thin prism formula. The second problem is a classic NEET/JEE scenario combining a prism with a plane mirror.

Watch from 00:51:30 to 01:00:56. The first problem is a direct application of the formula. For the second problem, carefully trace the total deviation: the initial deviation by the prism, and the subsequent deviation upon reflection from the mirror.

The mirror problem highlights an important skill: breaking a complex problem into sequential steps. The total deviation is the sum of deviations from each optical element the ray encounters.

Now, let's revisit dispersive power with a problem that requires the approximation for the mean refractive index, , which we discussed in the last lesson.

Ray optics L5 🔍 Prism, dispersion & combination |One Shot Marathon | Class 12 JEE 2022 | Shreyas sir

Let's solve a problem on dispersive power. This video segment is a good refresher and shows how to handle cases where the refractive index for the mean (yellow) color is not given.

Watch from 01:13:46 to 01:16:03. Notice the key first step is to calculate \mu_y = (\mu_v + \mu_r)/2 before applying the dispersive power formula. This is a very common requirement in exam problems.


3. Combination of Prisms

A more advanced set of problems involves combining two prisms (usually made of different materials like crown and flint glass) to achieve a specific outcome. The prisms are typically placed with their refracting angles oriented oppositely.

There are two primary configurations you must master:

Case 1: Deviation without Dispersion (Achromatic Combination)
The goal is to bend a beam of white light without splitting it into colors. The emergent ray is white and deviated.

  • Condition: The net angular dispersion is zero. .
  • Formula:
  • Net Deviation:

Case 2: Dispersion without Deviation (Direct-Vision Spectroscope)
The goal is to split white light into a spectrum, but have the mean (yellow) ray emerge parallel to the incident direction.

  • Condition: The net deviation of the mean ray is zero. .
  • Formula:
  • Net Dispersion:

Let's see an example of Case 1 (Achromatic Combination) being solved.

Ray optics L5 🔍 Prism, dispersion & combination |One Shot Marathon | Class 12 JEE 2022 | Shreyas sir

This final video clip explains how to set up and solve a problem for an achromatic (no dispersion) combination of prisms.

Watch from 01:23:00 to 01:29:13. The key is to start by setting the angular dispersion of the first prism equal to the angular dispersion of the second prism ( heta_1 = heta_2) and then solve for the unknown.


4. NEET Practice Drill

Now it's your turn. The following resource contains a large bank of NEET-style questions. I have selected a few that cover the concepts we've discussed. Try to solve them on your own before looking up the answers.

Problems on Ray Optics and Optical Instruments for NEET

This PDF from Disha Publication contains a comprehensive set of practice problems. We will use this to test your skills.

For the problems listed below, you can find the questions in the sections starting on pages 381 and 387. The detailed solutions are provided starting on page 389. I recommend attempting all problems before checking the solutions.

NEET-Style Problem Set

Attempt to solve the following problems from the "Problems on Ray Optics" PDF (LINK):

  1. Question 131: For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index lies between...? (Tests your understanding of the prism formula's limits).
  2. Question 132: Compares the minimum deviation for red and blue light. (Tests your understanding of how affects ).
  3. Question 135: A prism with one silvered surface. A ray returns back along the same path. Find the refractive index. (A classic combination of refraction and reflection).
  4. Question 136: The refractive index is given as . Find the angle of minimum deviation. (Requires manipulating the prism formula).
  5. Question 138: A combination of prisms produces dispersion without deviation. Find the angle of the second prism. (Direct application of the formula for Case 2).
  6. Question 140: A ray passes through an equilateral prism such that and . Find the angle of deviation. (A clever problem that uses the basic deviation formula).
Show hints and final answers
  1. Q131: Set in the prism formula and find the range of . You'll get . Since , what is the range of ? Answer: (b) lies between and 2.
  2. Q132: Recall that . How does change when increases in the prism formula? Answer: (a) D1 < D2.
  3. Q135: If the ray retraces its path, it must strike the silvered surface normally (at 90°). This means . Use to find . Then apply Snell's law at the first surface with . Answer: (b) 2 cos A.
  4. Q136: Substitute into the prism formula and solve for . Answer: (a) 180° – 2A.
  5. Q138: This is dispersion without deviation. Use the condition . You are given and . You need to find . Answer: (b) 10°.
  6. Q140: Given , , and . First, find and . Then use the general deviation formula . Answer: (d) 30°.

Conclusion

Excellent work today. We've methodically applied our entire prism toolkit to a range of NEET-style problems. The key to success is not just knowing the formulas, but recognizing which one to apply based on the problem's conditions.

Key Takeaways:

  • Always identify the type of problem first: minimum deviation, thin prism, or a combination.
  • For minimum deviation, use the special conditions (, ) to simplify the problem.
  • For combinations of prisms, the key is to correctly set up the condition: either net dispersion is zero () or net deviation is zero ().
  • Don't be afraid to break complex problems (like those with mirrors) into a sequence of simpler steps.

Preview of the Next Lesson:
We have now completed our study of prisms. In the next module, we will move on to the next major topic in Ray Optics: Thin Lenses. We will start by learning how to construct ray diagrams for convex and concave lenses to determine image characteristics, which aligns perfectly with your preference for mastering visual representations before tackling the mathematics.