Hello! Welcome to your seventh lesson in the Mathematics Mastery Sprint.
In our last lesson, we mastered a four-step algorithm for rearranging complex formulae, focusing on how factorisation is the key to isolating a variable that appears multiple times. This skill in methodical algebraic manipulation is a perfect foundation for today's topic.
We're now moving on to another crucial area of algebra: solving simultaneous equations. You'll learn how to find the unique values for two unknown variables that satisfy two different equations at the same time. This is a fundamental skill that not only appears as a standalone question but is also embedded in multi-step problems involving geometry, costs, and other real-world scenarios.
Learning Outcome: Formulate and solve pairs of linear simultaneous equations using elimination and substitution methods.
What are Simultaneous Equations?
Imagine you're told that two numbers, x and y, add up to 10 (x + y = 10). There are infinite possibilities: x could be 1 and y could be 9, or x could be 5.5 and y could be 4.5, and so on.
Now, what if you're also told that the difference between these same two numbers is 4 (x - y = 4)? This second condition constrains the possibilities. There is now only one pair of values for x and y that is true for both equations simultaneously. Our goal is to find that unique solution.
We will focus on two key algebraic methods to do this: elimination and substitution.
Method 1: The Elimination Method
The elimination method aims to remove one of the variables by adding or subtracting the two equations. This works best when the equations are both in the form ax + by = c.
To start, let's watch a video that demonstrates the core mechanics of this method.
Solving Systems of Equations By Elimination & Substitution With 2 Variables
This video from The Organic Chemistry Tutor clearly explains the different scenarios you'll encounter when using the elimination method. Pay attention to how the equations are manipulated to make the coefficients match.
Watch from the beginning to 03:45. The first example (00:00 - 01:32) shows the simplest case where you can immediately add the equations. The second example (01:32 - 03:45) shows the more common case where you must first multiply one equation to make the coefficients of a variable match.
The Core Process of Elimination
As you saw, the process depends on the coefficients of the variables:
- Label your equations (1) and (2). This is good practice for keeping your work clear.
- Check the coefficients of
xandyin both equations.- Case A (Opposite Coefficients): If the coefficients of one variable are opposites (e.g.,
+3yand-3y), you can add the two equations to eliminate that variable. - Case B (Same Coefficients): If the coefficients of one variable are the same (e.g.,
+5xand+5x), you can subtract one equation from the other to eliminate it. - Case C (Different Coefficients): If no coefficients match, multiply one or both equations by a number to create a match. Aim for the Lowest Common Multiple (LCM) of the coefficients. For example, to match
2yand3y, you would multiply the first equation by 3 (to get6y) and the second by 2 (to get6y).
- Case A (Opposite Coefficients): If the coefficients of one variable are opposites (e.g.,
- Solve the resulting single-variable equation.
- Substitute the value you just found back into one of the original equations to find the second variable.
- Check your answer by substituting both values (
xandy) into the other original equation. This is a crucial step to catch any arithmetic errors, which you've noted can be an issue.
A handy rule to remember for step 2 is SAD-SAM:
- If the signs are the Same, you Subtract.
- If the signs are Different, you Add.
Let's review this process with a detailed text example.
Simultaneous Equations - Cambridge (CIE) IGCSE Maths
The following resource from Save My Exams provides a concise, step-by-step summary of the elimination method, reinforcing what you've just seen in the video. It also includes a fully worked example typical of an IGCSE paper.
First, read the section 'How do I solve linear simultaneous equations by elimination?'. Then, carefully study the 'Worked Example' that follows, where they solve the system 5x + 2y = 11 and 4x - 3y = 18. Notice how they multiply both equations to make the 'y' coefficients match (6y and -6y) and then add the equations.
Method 2: The Substitution Method
The substitution method involves rearranging one equation to make one variable the subject (e.g., y = ...) and then substituting this expression into the other equation.
This brings us to a key strategic point you've mentioned: choosing the most efficient method.

The Core Process of Substitution
- Look for a variable with a coefficient of 1 or -1. Rearrange that equation to make that variable the subject. For example, rearrange
3x + y = 10intoy = 10 - 3x. - Substitute this expression into the other equation. This creates a new equation with only one variable.
- Solve this new equation.
- Substitute the result back into your rearranged equation from step 1 to find the second variable.
- Check your answer using the original equation you didn't rearrange.
Let's see this in action.
Solving Systems of Equations By Elimination & Substitution With 2 Variables
This next segment from The Organic Chemistry Tutor demonstrates the substitution method. Notice how it reduces the problem to solving a linear equation, a skill you are already comfortable with.
Watch from 03:45 to 10:28. The first example (03:45 - 05:50) shows a case where one equation is already given as 'y = ...'. The second, more complex example (07:24 - 10:28) shows how to first rearrange an equation before substituting.
Test your understanding!
Consider the simultaneous equations:
x - 2y = 34x + 5y = 21
Which method (elimination or substitution) would be more efficient here, and why? Describe your first step.
Show answer
Substitution would be more efficient. The x in the first equation has a coefficient of 1, making it very easy to rearrange.
First step: Rearrange equation (1) to make x the subject: x = 3 + 2y. You would then substitute (3 + 2y) for x in the second equation.
(While elimination would also work, it would require multiplying the first equation by 4 and then subtracting, which involves an extra step.)
Formulating and Solving from Word Problems
In IGCSE exams, you will often need to formulate the equations yourself from a written description before you can solve them. This is where your problem-solving skills come into play.
The process is:
- Define your variables: State clearly what
xandy(or any letters) represent. E.g., "Letcbe the cost of a coffee andtbe the cost of a tea." - Translate the information: Read the problem carefully and write down two distinct equations based on the information given.
- Solve: Choose the most efficient method (elimination or substitution) to solve the system.
- Answer in context: State your final answer clearly, making sure to include units (£, cm, etc.) and relate it back to the original question.
The following video works through several excellent examples of this, including one that directly relates to your weakness with "show that" questions in a geometric context.
GCSE Maths Revision - Solving simultaneous equations in context (2)
This video from HEGARTYMATHS is crucial as it focuses entirely on setting up and solving equations from context. The examples are very similar to what you'll find in your exam papers.
Watch the first three examples (from 00:26 to 08:40). Pay special attention to Example 3 (starting at 05:14). It involves a rectangle and asks you to 'show that' an equation is true. This is a perfect example of how forming an equation from geometric properties is the method for 'showing' what is required.
By watching that geometry example, you can see that "show that" in this context simply means "use the properties of a rectangle (opposite sides are equal) to form an algebraic equation and simplify it to the required format". This directly tackles one of your identified weak points.
Conclusion
Today, we've added a vital tool to your algebraic toolkit. You now have two reliable methods for solving linear simultaneous equations and a strategy for choosing the most efficient one. More importantly, you've seen how to apply these methods to word problems, translating real-world scenarios into solvable mathematical systems.
Key Takeaways:
- Elimination Method: Best when both equations are in
ax + by = cform. Make coefficients of one variable match, then add or subtract to eliminate it. Remember: SAD-SAM (Same signs -> Subtract, Different signs -> Add). - Substitution Method: Most efficient when one variable has a coefficient of 1 or -1, allowing for easy rearrangement.
- Word Problems: Follow the four-step process: Define -> Translate -> Solve -> Answer in context.
- Always check your work! Substituting your final
xandyvalues back into an original equation is the best way to guarantee accuracy and avoid losing marks to small errors.
Preview of the Next Lesson:
We will build directly on today's skills in the next lesson as we tackle a slightly more complex topic: solving simultaneous equations where one is linear and one is non-linear. This will require us to combine the substitution method with our knowledge of solving quadratic equations.